Difference between revisions of "Falling Body with Air Resist"

From apimba
Jump to navigation Jump to search
Line 28: Line 28:
  
 
v = mg/k - Ce<sup>-kt/m</sup>
 
v = mg/k - Ce<sup>-kt/m</sup>
 +
 +
If at time 0, the body is at rest then v(0) = 0 = mg/k - C so C = mg/k
 +
 +
therefore v = mg/k - mg/ke<sup>-kt/m</sup>

Revision as of 07:04, 5 May 2020

Ftotal = Fgrav - Fair

ma = mg - kv where k units are kg/sec

mdv/dt = mg - kv

put into standard order:

mdv/dt + kv = mg

dv/dt + vk/m = g

find u = e∫k/mdt = ekt/m

multiply by u:

ekt/mdv/dt + ekt/mvk/m = gekt/m

d/dt(vekt/m) = gekt/m

integrate both sides:

vekt/m + C1 = gm/kekt/m + C2

solve for v:

v = mg/k - (C1 + C2)/ekt/m

v = mg/k - Ce-kt/m

If at time 0, the body is at rest then v(0) = 0 = mg/k - C so C = mg/k

therefore v = mg/k - mg/ke-kt/m